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B
250663
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C
24951
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D
24954
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Solution
The correct option is A249663 From the expansion of binomial (1+x)50=C0+C1x+C2x2+C3x3+⋯+C50x50 integrating both sides w.r.t x from the limits −1 to 1, we get [(1+x)5151]1−1=[C0x+C1x22+C2x33+⋯+C50x5151]1−1 Now applying the limits, we get 25151=2[C0+C23+C45+⋯+C5051] ∴Mean=sum of numberstotal numbers=25051×26=249663