Question

Mean optical power launched into an 8 km fiber is 120 $\mu$W and mean output power is 4 $\mu$W, then the overall attenuation is (Given log 30 = 1.477)

• A. 14.77 dB
• B. 16.77 dB
• C. 3.01 dB
• D. None of these

Answer 1

The correct option is A 14.77 dB

Attenuation = 10log $\frac{120}{4}$ = 10log 30
= 10 $\times$ 1.4771 = 14.77dB