Mechanically work done is equal to (symbols have their usual meanings)

W = F / S

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W = F S

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W = F + S

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W = F - S

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Solution

The correct option is B $W = F S$
Work done is defined as product of the force and the distance over which the force is applied.

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Similar questions

Q. When W=F *S *costheta and W= F* costheta *S formula are used?

A ball of mass 20g is accelerated by a force from 20m/s to 50 m/s. Calculate the work done by the force. Also calculate the force applied if the displacement brought about by the force is 10m.

A block of mass 2.0 kg is pushed down an inclined plane of inclination $37^{\circ}$ with a force of 20 N acting parallel to the incline. It is found that the block moves on the incline with an acceleration of $10 m / s^{2}$ . If the block started from rest, find the work done $(W_{F})$ by the applied force, work done $(W_{g})$ by the weight of the block and work done $(W_{f})$ by the frictional force acting on the block in the 1st second. Take $g = 10 m / s^{2}$ .

Q. Mechanically, work done is equal to (symbols have their usual meanings).

Why does work done not depend on time ?

If we take

W=F.s

=>W=ma.s

=>W=m(v-u/t).s....…………(I)

From this equation (I) we can conclude that work done is inversely proportional to time.

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Mechanically work done is equal to (symbols have their usual meanings)

The correct option is B W=FSWork done is defined as product of the force and the distance over which the force is applied.

The correct option is B $W = F S$
Work done is defined as product of the force and the distance over which the force is applied.