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Question

Median of 2nC0,2nC1,2nC2,....,2nCn (when n is even) is

A
2nCn12
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B
2nCn2
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C
2nCn+12
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D
None of these
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Solution

The correct option is A 2nCn2
Given observations 2nC0,2nC1,2nC2,....,2nCn
Here number of terms =n+1 ....(odd)
Median =(n2+1) th term
=2nCn2

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