Question

Medium 1 has the electrical permittivity ${\epsilon }_1=1.5{\epsilon }_0$ farad/m and occupies the region to the left of x = 0 plane. Medium 2 has the electrical permittivity ${\epsilon }_2=2.5{\epsilon }_0$ farad/m and occupies the region to the right of x = 0 plane. If $E_1$ in medium 1 is $E_1=(2u_x-3u_y+1u_z)$ volt/m, then $E_2$ in meidum 2 is

• A. $(2.0u_x-7.5u_y+2.5u_z$)volt/m
• B. $(2.0u_x-2.0u_y+0.6u_z$)volt/m
• C. $(1.2u_x-3.0u_y+1.0u_z$)volt/m
• D. $(1.2u_x-2.0u_y+0.6u_z$)volt/m

Answer 1

The correct option is C $(1.2u_x-3.0u_y+1.0u_z$)volt/m

Ans : (c)
${\overrightarrow{E}}_1=2u_x-3u_y+1u_z$
${\overrightarrow{E}}_{1t}=-3u_y+u_z=E_{2t}(x=0plane)$

${\overrightarrow{E}}_{1n}=2u_x$

${\overrightarrow{D}}_{1n}={\overrightarrow{D}}_{2n}=\in \overrightarrow{E}$

$\Rightarrow {\in }_1{\overrightarrow{E}}_{1n}={\in }_2{\overrightarrow{E}}_{2n}$

$=1.5{\in }_o.2u_x=2.5{\in }_o.{\overrightarrow{E}}_{2n}$

${\overrightarrow{E}}_{2n}=\frac{3}{2.5}{u}_x=1.2u_x$

${\overrightarrow{E}}_2={\overrightarrow{E}}_{2t}+{\overrightarrow{E}}_{2n}$

${\overrightarrow{E}}_2=-3u_y+u_z+1.2u_x$