Meenakshee cycles to her school at an average speed of 12 km/h and takes 20 minutes to reach her school. If she wants to reach her school in 12 minutes, what should her average speed be? [3 MARKS]

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Solution

Concept: 1 Mark
Application: 2 Marks

As the speed increases, the time taken decreases. Therefore, time and speed are inversely proportional.

$S p e e d \times t i m e = c o n s t a n t$

$12 \times 20 = s \times 12$

$s = \frac{12 \times 20}{12}$

$s = 20 k m / h$

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Q. Meenakshi cycles to her school at an average speed of 12 km/hr and takes 20 minutes to reach her school. If she wants to reach her school in 12 minutes, her average speed should be:

Question 11

Meenakshee cycles to her school at an average speed of 12 km/h and takes 20 minutes to reach her school. If she wants to reach her school in 12 minutes, her average speed should be
$(a) \frac{20}{3} k m / h$
(b)16 km/h
(c)20 km/h
(d) 15 km/h

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Meenakshee cycles to her school at an average speed of 12 km/h and takes 20 minutes to reach her school. If she wants to reach her school in 12 minutes, what should her average speed be? [3 MARKS]

Concept: 1 Mark Application: 2 Marks As the speed increases, the time taken decreases. Therefore, time and speed are inversely proportional. Speed×time=constant 12×20=s×12 s=12×2012 s=20 km/h

Concept: 1 Mark
Application: 2 Marks

As the speed increases, the time taken decreases. Therefore, time and speed are inversely proportional.

$S p e e d \times t i m e = c o n s t a n t$

$12 \times 20 = s \times 12$

$s = \frac{12 \times 20}{12}$

$s = 20 k m / h$