Question

Melting point of arachidonic acid is

• A. ${13.4}^{\circ }C$
• B. $-5^{\circ }C$
• C. $-{11}^{\circ }C$
• D. $-{49.5}^{\circ }C$

Answer 1

Answer: (D)

$-{49.5}^{\circ }C$

Arachidonic acid is a lipid. Lipids could be simple fatty acid or glycerol. Arachidonic acid is a fatty acid. A fatty acid molecule is an unbranched chain of carbon atoms having a carboxylic group attached to an R group. The R group could be a methyl ($-C{H}_3$) or ethyl ($-C_2{H}_5$) or higher number of $-C{H}_2$ groups (1 to 19 carbons).

Arachidonic acid has 20 carbon atoms including the carboxyl group. Its melting point is $-{49.5}^{\circ }C$.