1
Question
Mendel's law of independent assortment can be demonstrated by
Mendel's law of independent assortment can be demonstrated by
Open in App
Solution
The correct option is D Dihybrid cross
A.Test cross –
crossing of F1 individual with homozygous recessive progeny is called
Test cross. It is used to determine whether F1 progeny is homozygous
or heterozygous.
B.Back cross –
Crossing F1 progeny with any one of the parents.
C.Monohybrid cross –
Cross is made between a homozygous dominant parent to another homozygous
recessive parent on the basis of one character. By using this cross Mendel
postulated Law of dominance and Law of Segregation.
D.Dihybrid cross – Cross
is made between a homozygous dominant parent to another homozygous recessive
parent on the basis of twocharacters. By using this cross Mendel postulated Law
of Independent assortment.
So,
the correct option is ‘Dihybrid cross’.
A.Test cross – crossing of F1 individual with homozygous recessive progeny is called Test cross. It is used to determine whether F1 progeny is homozygous or heterozygous.
B.Back cross – Crossing F1 progeny with any one of the parents.
C.Monohybrid cross – Cross is made between a homozygous dominant parent to another homozygous recessive parent on the basis of one character. By using this cross Mendel postulated Law of dominance and Law of Segregation.
D.Dihybrid cross – Cross is made between a homozygous dominant parent to another homozygous recessive parent on the basis of twocharacters. By using this cross Mendel postulated Law of Independent assortment.
So, the correct option is ‘Dihybrid cross’.Suggest Corrections
0
Similar questions
View More
Join BYJU'S Learning Program
Explore more
Join BYJU'S Learning Program
