Question

Mention the expression for velocity and acceleration of a particle executing SHM.

Answer 1

The velocity of the particle executing SHM at any instant of time is given by
$v=A\omega \cos \omega t=\omega \sqrt{A^2-y^2}$
The acceleration of the particle executing SHM is given by
$a=\frac{dv}{dt}=-A{\omega }^2\sin \omega t=-{\omega }^{2}y$
where $\omega$ - angular frequency, $A$ - amplitude, $y$ - displacement of particle from its mean position in time $t$ .