Mention the first five elements of the periodic table having odd atomic numbers. Logically choose the one with the maximum electronegativity and explain your logic.

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Solution

Hydrogen (H), Lithium (Li), Boron (B), Nitrogen (N) and Fluorine (F) are the first five elements with odd atomic numbers 1, 3, 5, 7, 9, respectively.
In these, Hydrogen (H) and Nitrogen (N) are non-metals, Lithium(Li) is an alkali metal, Boron (B) is a metalloid, and Fluorine (F) is a halogen. Except for Hydrogen, the other four elements belong to the second period of the periodic table.
The tendency of an atom to attract the electrons towards itself is called ‘Electronegativity’.
Electronegativity increases across a period (from left to right) and decreases down the group (from top to bottom).
By moving from left to right of the table, electrons in the atoms have a tight bond with their nucleus because of strong nuclear energy.
Elements on the top-right side of the periodic table have more electronegativity.
In these first five odd elements, Fluorine has maximum electronegativity because it is present on the top right side in the 17^th group of the periodic table. Also, fluorine needs one electron to complete its octet, and due to its smaller size, it is most electronegative.

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