You visited us 3 times! Enjoying our articles? Unlock Full Access!

Density of Regular Solids

Mercury has a...

Question

Mercury has a density of $13.6 g / c m^{3}$ . What volume of mercury must be taken to obtain $225 g$ of the metal?

16.54 c m^{3}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

13.86 c m^{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

14.54 c m^{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

11.86 c m^{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $16.54 c m^{3}$
Given, density of mercury, $ρ = 13.6 g / c m^{3}$ ;
mass of mercury, $m = 225 g$ ;
volume of mercury, $V = ?$
Now, density, $ρ = \frac{M a s s}{V o l u m e} = \frac{m}{V}$
or $V = \frac{m}{ρ} = \frac{225}{13.6} = 16.54 c m^{3}$

Suggest Corrections

Similar questions

0.8 g / {c m}^{3}

13.6 g / {c m}^{3}

g / {c m}^{3}

= 0.8 g / {c m}^{2}

= 13.6 g / {c m}^{3}

g / {c m}^{3}

0.8 {g/cm}^{2}

13.6 {g/cm}^{3}

{g/cm}^{3}

13.6 g / {c m}^{3}

b

0.8 {g/cm}^{3})

13.6 {g/cm}^{3})

{g/cm}^{3}

Join BYJU'S Learning Program