Meso-and racemic-2, 3-dibromobutane on reaction with NaI in acetone give:
A
E-But-2-ene and Z-But-2-ene, respectively
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B
Z-But-2-ene and E-But-2-ene, respectively
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C
both give E-But-2-ene
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D
both give Z-But-2-ene
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Solution
The correct option is A E-But-2-ene and Z-But-2-ene, respectively i. Meso compound + Anti-elimination of Br2→ trans or E-But-2-ene. ii. Racemic compound + Anti-elimination of Br2→ cis or Z-But-2-ene. So the answer is (a).