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Question

Metal nitrate (A) on heating decomposes, leaving a residue (B) which goes into the solution with dil. HCl. The solution of (B) gives a white ppt. with an ammonium carbonate solution. Ppt. C dissolves in dil. HCl and the solution is treated with potassium chromate to yellow ppt. (D). Solution V with dil.H2SO4 also gives white ppt. (E) insoluble in dil. HCl and nitric acid. Precipitate (E) is part of white pigment lithopone.

The yellow precipitate (D) is:

A
PbCrO4
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B
BaCrO4
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C
CaCrO4
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D
none of these
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Solution

The correct option is B BaCrO4
The sequence of reactions is given below.
Ba(NO3)2heatBaOdil HCl−−−BaCl2AB

BaOAmmonium carbonate−−−−−−−−−−−−BaCO3dilHCl−−−BaCl2Potassium chromate−−−−−−−−−−−BaCrO4dil H2SO4−−−−−BaSO4CDE
The white precipitate is of barium carbonate. The yellow precipitate (D) is of barium chromate. Barium sulfate precipitate is also white in color.

So, the correct option is B

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