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Byju's Answer

Standard XII

Chemistry

Characteristics of Equilibrium Constant

Metal nitrate...

Question

Metal nitrate $(A)$ on heating decomposes, leaving a residue $(B)$ which goes into the solution with dil. $H C l$ . The solution of $(B)$ gives a white ppt. with an ammonium carbonate solution. Ppt. $C$ dissolves in dil. $H C l$ and the solution is treated with potassium chromate to yellow ppt. $(D)$ . Solution $V$ with dil. $H_{2} S O_{4}$ also gives white ppt. $(E)$ insoluble in dil. $H C l$ and nitric acid. Precipitate $(E)$ is part of white pigment lithopone.

The yellow precipitate $(D)$ is:

P b C r O_{4}

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B a C r O_{4}

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C a C r O_{4}

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none of these

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Solution

The correct option is B $B a C r O_{4}$
The sequence of reactions is given below.
$B a (N O_{3})_{2} h e a t - - \to B a O d i l H C l - --- \to B a C l_{2} A B$

$B a O A m m o n i u m c a r b o n a t e - ------------ \to B a C O_{3} d i l H C l - --- \to B a C l_{2} P o t a s s i u m c h r o m a t e - ----------- \to B a C r O_{4} d i l H_{2} S O_{4} - ----- \to B a S O_{4} C D E$
The white precipitate is of barium carbonate. The yellow precipitate $(D)$ is of barium chromate. Barium sulfate precipitate is also white in color.

So, the correct option is $B$

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Similar questions

Q. A white powder

A

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and the solution gives a white ppt with

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A

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(G)

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Q. On mixing the aqueous solutions of compounds

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K_{2} C r O_{4}

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