Metal spheres, each of radius 2 cm, are packed into a rectangular box of internal dimension $16 c m \times 8 c m \times 8 c m$ when 16 spheres are packed the box is filled with preservative liquid. Find the volume of this liquid .

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Solution

Volume of 16 spheres $= \frac{4}{3} \times \frac{22}{7} \times 2^{3} \times 16 = 536.36 c m^{3}$

Volume of rectangle $= 16 \times 8 \times 8 = 1024 c m^{3}$

Volume of preservative liquid $= 1024 b - 536.36 = 487.64 c m^{3}$

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Metal spheres, each of radius 2 cm, are packed into a rectangular box of internal dimension 16 cm×8 cm×8 cm when 16 spheres are packed the box is filled with preservative liquid. Find the volume of this liquid .

Volume of 16 spheres =43×227×23×16=536.36 cm3 Volume of rectangle =16×8×8=1024 cm3 Volume of preservative liquid =1024b−536.36=487.64 cm3

Metal spheres, each of radius 2 cm, are packed into a rectangular box of internal dimension $16 c m \times 8 c m \times 8 c m$ when 16 spheres are packed the box is filled with preservative liquid. Find the volume of this liquid .

Volume of 16 spheres $= \frac{4}{3} \times \frac{22}{7} \times 2^{3} \times 16 = 536.36 c m^{3}$

Volume of rectangle $= 16 \times 8 \times 8 = 1024 c m^{3}$

Volume of preservative liquid $= 1024 b - 536.36 = 487.64 c m^{3}$