Question

Metal X form 2 oxide. Formula of $1^{st}$ is ${XO}_2$ $1^{st}$ oxide contain $50\%O_2$. If $2^{nd}$ oxide contain $60\%O_2$ .Formula of $2^{nd}$ oxide?

• A. $X_{2}O$
• B. ${XO}_3$
• C. $X_2{O}_3$
• D. $X_3{O}_2$

Answer 1

The correct option is C $X_2{O}_3$

Given that in${XO}_2,50$% of $O_2$ is present

$2O_2=32\frac{32}{M+32}=0.5$

now ,given that is second oxide 60% of is present let no. of metal X contained in this oxide.is n then,

$\frac{32}{n\times 32+32}=0.6\frac{1}{n+1}=0.61=0.6n+0.6n=\frac{0.4}{0.6}=\frac{2}{3}{X}_2{O}_3$

is formula of compound