Metal X is found in earth's crust. This metal forms a reddish brown substance when exposed to moist air. When a blue colored solution Y is stored in a container made of X, the solution turns green and a reddish brown metal Z gets deposited on the container.
X, Y and Z are respectively:

C u, C u S O_{4}, F e

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Z n, Z n S O_{4}, F e

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F e, C u S O_{4}, C u

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C u, F e S O_{4}, F e

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Solution

The correct option is C $F e, C u S O_{4}, C u$
Metal X is $F e$ which is found in earth's crust.
$2 F e + \frac{3}{2} O_{2} + x H_{2} O \to F e_{2} O_{3} . x H_{2} O$

$F e (s) + C u S O_{4} b l u e (a q) \to F e S O_{4} g r e e n (a q) + C u (s)$

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Metal X is found in earth's crust. This metal forms a reddish brown substance when exposed to moist air. When a blue colored solution Y is stored in a container made of X, the solution turns green and a reddish brown metal Z gets deposited on the container. X, Y and Z are respectively:

The correct option is C Fe,CuSO4,CuMetal X is Fe which is found in earth's crust. 2Fe+32O2+xH2O→Fe2O3.xH2O Fe(s)+CuSO4blue(aq)→FeSO4green(aq)+Cu(s)

Metal X is found in earth's crust. This metal forms a reddish brown substance when exposed to moist air. When a blue colored solution Y is stored in a container made of X, the solution turns green and a reddish brown metal Z gets deposited on the container.
X, Y and Z are respectively:

The correct option is C $F e, C u S O_{4}, C u$
Metal X is $F e$ which is found in earth's crust.
$2 F e + \frac{3}{2} O_{2} + x H_{2} O \to F e_{2} O_{3} . x H_{2} O$

$F e (s) + C u S O_{4} b l u e (a q) \to F e S O_{4} g r e e n (a q) + C u (s)$