Metalic ion found in blood of mollusc is

C u^{+ +}

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F e^{+ +}

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C o^{+ +}

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M g^{+ +}

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Solution

The correct option is A $C u^{+ +}$
Hemocyanin is oxygen carrier of many molluscs and arthropods contains two $C u^{+ +}$ ions in its active site. These are suspended directly in the hemolymph. On oxidation, during the gaseous stage, the copper ions change its colour from clear to blue. Copper ions are complexed by three histidine residues that form the distorted pyramidal geometry of each atom. The space between the copper atoms facilitates the bonding of the two copper atoms to each dioxygen molecule. So, the correct answer is option A.

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Similar questions

Q. Both metals

M g

and

F e

can reduce copper from a solution having

{C u}^{2 +}

ion, according to equilibria.

M g (s) + {C u}^{2 +} (a q) ⇌ {M g}^{2 +} (a q) + C u (s); K_{1} = 6 \times 10^{90}

F e (s) + {C u}^{2 +} (a q) ⇌ {F e}^{2 +} (a q) + C u (s); K_{1} = 3 \times 10^{26}

Which metal will remove cupric ion from the solution to a greater extent?

Q. Both

M g

and

F e

metal can reduce copper from a solution having

C u^{2 +}

ion, according to equilibria.

M g_{(s)} + C u^{2 +} ⇋ M g^{2 +} + C u_{(s)}; K_{1} = 6 \times 10^{90}

F e_{(s)} + C u^{2 +} ⇋ F e^{2 +} + C u_{(s)}; K_{2} = 3 \times 10^{26}

Choose the correct option regarding above equilibrium.

Which metal is considered best for protecting the other metal?

$E {^{0}}_{F e^{2 +} / F e} = - 0.44 V, E {^{0}}_{Z n^{2 +} / Z n} = - 0.76 V$
$E {^{0}}_{M g^{2 +} / M g} = - 2.37 V, E {^{0}}_{C u^{2 +} / C u} = - 0.34 V$

Q. Which of these ions

C u^{+}, C o^{3 +}, F e^{2 +}

is stable in the aqueous medium?

Given:

E_{C u^{2 +} / C u^{+}}^{0} = 0.15 V; E_{C u^{+} / C u}^{0} = 0.53 V E_{C o^{3 +} / C o^{2 +}}^{0} = 1.82 V; E_{F e^{3 +} / F e^{2 +}}^{0} = 0.77 V E_{F e^{2 +} / F e}^{0} = - 0.44 V; E_{O_{2}, H^{+} / H_{2} O}^{0} = 1.23 V

Q. The order of reactivity of metals is
(a) K > Na > Ca > Au
(b) K > Ca > Na > Mg
(c) Fe > Na > Mg > Au
(d) Cu > Fe > K > Na

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