Question

Metallic gold crystallises in fcc lattice. The length of the cubic unit cell (a) is $4.07\mathring{A}$. What is the closest distance between the gold atoms?

• A. $1.44$
• B. $2.88$
• C. $4.32$
• D. None of the above

Answer 1

The correct option is B $2.88$

Closest distance between two atoms in fcc lattice is $\frac{a}{\sqrt{2}}=2.88$