Metallic magnesium is prepared by-Reduction of MgO-by coke-Reduction of MgO-by coke-Displacement of Mg-by iron from MgSO-4-solution-Electrolysis of molten MgCl-2-

The correct option is D Electrolysis of molten MgCl_2 MgCl_2 Electrolysis Mg^+2 + 2Cl (Molten) Cation Anion Anode 2Cl^ → 2Cl + ...

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Standard IX

Chemistry

Extraction of Magnesium

Metallic magn...

Question

Metallic magnesium is prepared by

Reduction of MgO by coke

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Reduction of MgO by coke

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Displacement of Mg by iron from $M g S O_{4}$ solution

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Electrolysis of molten $M g C l_{2}$

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Solution

The correct option is D
Electrolysis of molten $M g C l_{2}$

$M g C l_{2} E l e c t r o l y s i s - -------- \to M g^{+ 2} + 2 C l$

(Molten) Cation Anion

Anode - $2 C l^{-} \to 2 C l + 2 e^{-}, C l + C l \to C l_{2}$

Cathode - $M g^{+ 2} + 2 e^{-} \to M g$

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Similar questions

Q. Carbon cannot be used to produce magnesium by chemical reduction of MgO because:

The two metals which are extracted by means of electrolytic reduction of their molten salt are:
(a) magnesium and manganese (b) iron and aluminium
(c) zinc and magnesium (d) magnesium and aluminium

Q. Metallic magnesium is prepared by:

$M g + H_{2} S O_{4} \to A - - + H_{2} (M g) (d i l u t e)$

$M g + 2 H_{2} S O_{4} \to A - - + B - - + 2 H_{2} O . (C o n c e n t r a t e d)$ A & B are

Q. STATEMENT-1 : Magnesium can be prepared by the electrolysis of aq.

M g C l_{2}

STATEMENT-2 : The reduction potential of

M g^{2 +}

is much lower than that of

H^{+}

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Metallic magnesium is prepared by

The correct option is D Electrolysis of molten MgCl2 MgCl2 Electrolysis−−−−−−−−−→ Mg+2 + 2Cl (Molten) Cation Anion Anode - 2Cl− → 2Cl + 2e−,Cl + Cl → Cl2 Cathode - Mg+2 + 2e− → Mg

The correct option is D
Electrolysis of molten $M g C l_{2}$

$M g C l_{2} E l e c t r o l y s i s - -------- \to M g^{+ 2} + 2 C l$

(Molten) Cation Anion

Anode - $2 C l^{-} \to 2 C l + 2 e^{-}, C l + C l \to C l_{2}$

Cathode - $M g^{+ 2} + 2 e^{-} \to M g$