Metallic sodium reacts with methanol and ethanol to give:

O_{2}

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H_{2} O

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C O_{2}

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H_{2}

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Solution

The correct option is C $H_{2}$
A small piece of sodium is dropped into methanol and it reacts steadily to give off bubbles of hydrogen gas and leaves a colorless solution of sodium ethoxide.
$2 C H_{3} - C H_{2} - O H + 2 N a \to 2 C H_{3} C H_{2} - O^{-} N a^{+} + H_{2}$
$E t h a n o l$ $S o d i u m E t h o x i d e$

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