Methane cannot be prepared by hydrolysis of:

A l_{4} C_{3}

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B e_{2} C

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C a C_{2}

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All of these

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Solution

The correct option is C $C a C_{2}$
Methane cannot be prepared by $C a C_{2.}$ On hydrolysis, it produces acetylene.
Remaining other carbides produce methane.
$A l_{4} C_{3} + 12 H_{2} O \to 4 A l (O H)_{3} + 3 C H_{4}$
$B e_{2} C + 2 H_{2} O \to 2 B e O + C H_{4}$
$C a C_{2} + 2 H_{2} O \to C a (O H)_{2} + C_{2} H_{2}$

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