Question

Methane does not react with chlorine in dark.

• A. True
• B. False

Answer 1

The correct option is A True

i. $C{H}_4$ does not react with $C{l}_2$ in dark because the reaction proceeds via free-radical mechanism, Cl (chlorine radicals) are obtained from $C{l}_2$ in the presence of light.
ii. It is in accordance with Markovnikov's rule which predicts the stability of $2^{\circ }{C}^{\oplus }$ over $1^{\circ }{C}^{\oplus }$.