Methyl cyanide on reaction with sodium and $C_{2} H_{5} O H$ forms:

ethyl amine

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

ethanoic acid

No worries! We‘ve got your back. Try BYJU‘S free classes today!

ethanimine

No worries! We‘ve got your back. Try BYJU‘S free classes today!

none of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A ethyl amine
Methyl cyanide on reaction with sodium and ethanol forms ethylamine.
$C H_{3} - C \equiv N + 4 [H] N a / e t h a n o l - ------ \to C H_{3} - C H_{2} - N H_{2}$
In this reaction, the nitrile group is hydrogenated to form a primary amine. This is a useful method to increase the length of a carbon chain in preparing a primary amine which contains one more carbon atom than the alkyl halide from which alkyl cyanide is obtained.

Suggest Corrections

Similar questions

H_{2} {S O}_{4}

C_{2} H_{5} O H

A

A

N a / C_{2} H_{5} O H

Methyl cyanide on hydrolysis gives:

Join BYJU'S Learning Program