Methyl cyanide on reduction with sodium and alcohol gives

Methyl amine

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Ethyl amine

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Methyl alcohol

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Acetic acid

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Solution

The correct option is B Ethyl amine
$C H_{3} C N + 4 H N a, C_{2} H_{5} O H - ------- \to C H_{3} C H_{2} N H_{2}$

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Methyl cyanide on reduction with sodium and alcohol gives

The correct option is B Ethyl amine CH3CN+4HNa,C2H5OH−−−−−−−−→CH3CH2NH2

The correct option is B Ethyl amine
$C H_{3} C N + 4 H N a, C_{2} H_{5} O H - ------- \to C H_{3} C H_{2} N H_{2}$