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Hinsberg Test

Methylamine r...

Question

Methylamine reacts with $H N O_{2}$ to form:

C H_{3} - O - N = O

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C H_{3} - O - C H_{3}

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C H_{3} O H

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C H_{3} C H O

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Solution

The correct option is C $C H_{3} O H$
$C H_{3} N H_{2} + H N O_{2} N a N O_{2} + H C L - -------- \to C H_{3} - N_{2}^{+} C l^{-} H_{2} O - - \to C H_{3} O H + N_{2} + H C l$
methylamine

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Similar questions

C H_{3} O H + C_{2} H_{5} O H H^{+} - - \to

i) C H_{3} - C H_{2} - C H_{3} | C H - C H_{2} - O = C H_{2} - C H_{3}

i i) C H_{3} - C H_{2} - C H_{2} - O - C H_{3} | C | C H_{3} - C H_{3}

C H_{3} - O | | C - C H_{3}

X_{2}, O H^{-} - ---- \to

C H_{3} - O | | C - C H_{3}

\to X_{3} C - O | | C - C X_{3}

C H_{3} - O | | C - C H_{3}

O H^{-} - -- \to

C H_{3} - O | | C - O^{-} - C H X_{3}

C H_{3} - C H_{2} - O - C H_{2} - C H_{3}

C H_{3} - O | | C - C H_{3}

X_{2}, O H^{-} - ---- \to

C H_{3} - O | | C - C H_{3}

\to X_{3} C - O | | C - C X_{3}

C H_{3} - O | | C - C H_{3}

O H^{-} - -- \to

C H_{3} - O | | C - O^{-} - C H X_{3}

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