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Byju's Answer
Standard XII
Chemistry
Electrode Potential
Mg2+ + 2e-→ M...
Question
M
g
2
+
+
2
e
−
→
M
g
;
E
∘
c
e
l
l
(
V
)
=
−
2.37
C
u
2
+
+
2
e
−
→
C
u
;
E
∘
c
e
l
l
=
0.34
Analyze the data above.
Which substance should be used for electrode B in this galvanic cell?
A
M
g
2
+
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B
M
g
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C
C
u
2
+
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D
C
u
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Solution
The correct option is
D
C
u
In the given figure,
Electrons flow from A to B, which means A is anode and B is the cathode.
Cu is having higher reduction potential, so it will act as cathode.
Thus, electrode B is made of Cu.
Suggest Corrections
0
Similar questions
Q.
Which of the following set of metal electrodes can be used in the given galvanic cell?
Given:
M
g
2
+
(
a
q
)
+
2
e
−
→
M
g
(
s
)
;
E
0
=
−
2.37
V
C
u
2
+
(
a
q
)
+
2
e
−
→
C
u
(
s
)
;
E
0
=
0.34
V
A
g
+
(
a
q
)
+
e
−
→
A
g
(
s
)
;
E
0
=
0.80
V
Q.
The voltage of a cell whose half cell reactions are given below is
M
g
2
+
+
2
e
−
→
M
g
(
s
)
;
E
=
−
2.37
V
(anode)
C
u
2
+
+
2
e
−
→
C
u
(
s
)
:
E
=
+
0.34
V
(cathod)
Q.
Given:
(i)
C
u
2
+
+
2
e
−
→
C
u
,
E
∘
=
0.337
V
(ii)
C
u
2
+
+
e
−
→
C
u
+
,
E
∘
=
0.153
V
Electrode potential,
E
∘
for the reaction,
C
u
+
+
e
−
→
C
u
, will be
Q.
Refer to the following experimental data.
Half Reaction
Eo
I.
M
g
→
M
g
2
+
+
2
e
−
2.37V
II.
M
n
→
M
n
2
+
+
2
e
−
1.03V
III.
H
2
→
2
H
+
+
2
e
−
0.00V
IV.
C
u
→
C
u
2
+
+
2
e
−
-0.16V
What will be the standard reduction potential for the reaction:
M
g
+
M
n
2
+
→
M
g
2
+
+
M
n
?
Q.
a. Calculate e.m.f of cell for the reaction:
M
g
(
s
)
+
C
u
2
+
(
0.0001
M
)
→
M
g
2
+
(
0.001
M
)
+
C
u
(
s
)
Given that:
E
o
M
g
2
+
/
M
g
=
−
2.37
V
E
o
C
u
2
+
/
C
u
=
+
0.34
V
b. i) State Kohlrausch law.
ii) What is meant by limiting molar conductance.
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