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Question

Mg2C3 reacts with water forming propyne. C43 has:

A
Two sigma and two pi bonds
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B
Three sigma and one pi bonds
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C
Two sigma and one pi bonds
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D
Two sigma and three pi bonds
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Solution

The correct option is A Two sigma and two pi bonds
Mg2C3+4H2O2Mg(OH)2+C3H4
When propyne looses its four hydrogen, C43 is obtained.
The structure is: CCC3
It has two σ bonds and two π bonds.

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