wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Mg2C3 reacts with water forming propyne. C43 has:

A
Two sigma and two pi bonds
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
Three sigma and one pi bonds
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Two sigma and one pi bonds
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Two sigma and three pi bonds
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A Two sigma and two pi bonds
Mg2C3+4H2O2Mg(OH)2+C3H4
When propyne looses its four hydrogen, C43 is obtained.
The structure is: CCC3
It has two σ bonds and two π bonds.

flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
VBT and Orbital Overlap
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon