$M g + O_{2} \to M g O$
If $0.486 g$ of magnesium is fully oxidized, what mass of magnesium oxide should be produced?

0.806 g

M g O

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0.972 g

M g O

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0.646 g

M g O

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0.486 g

M g O

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Solution

The correct option is A $0.806 g$ $M g O$
$M g + O_{2} \to M g O$

$1 m o l e$ of $M g$ produces $1 m o l e$ of $M g O$ .
Molar mass of $M g O = 24 + 16 = 40$

So, $24 g$ $M g \to$ $40 g M g O$
$0.486 g$ $M g \to$ $(x)$

$\Rightarrow x = \frac{40 \times 0.486}{24} = 40 \times 0.02 = 0.806 g$

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