$M g$ on reaction with $C O_{2}$ gives A and gas B.
Identify A, B and the reducing and the oxidizing agents in the following above reaction.

M g O, C O, M g,

C O_{2}

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M g, C O_{2}

M g O, C O

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M g, M g O, C O, C O_{2}

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M g O, C O, C O_{2}

M g

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Solution

The correct option is B $M g O, C O, M g,$ $C O_{2}$
The reaction can be written as:
$M g + C O_{2} \to M g O + C O$
here oxidation number of Mg changes from 0 to +2 thus it is acting as a reducing agent. Similarly, the oxidation number of C is reduced from +4 to +2. Thus it is acting as an oxidizing agent.
Thus in this reaction, Mg is the reducing agent and $C O_{2}$ is the oxidising agent.Also A = MgO and B = CO

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Similar questions

C O_{2}

{2Mg(s) +O}_{2} (g) Heat - -- \to 2MgO(s)

Which of the following is an oxidising agent in $2 M g + O_{2} (g) \to 2 M g O (s)$

2 Mg (s) + {CO}_{2} (g) \to

M g {C O}_{3}

{C O}_{2}

M g {C O}_{3}

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