Question

$Mg\left(s\right)+H_{2}S{O}_4\left(dil\right)\to MgS{O}_4+\underset{–}{x}$

• A. $x=H_{2}O$
• B. $x=H_2$
• C. $x=S{O}_2$
• D. $x=SO$

Answer 1

The correct option is B $x=H_2$

All those metals which are more reactive than hydrogen, that is, those metals which lose electrons more easily than hydrogen, displace hydrogen from dilute acids to produce $H_2$ gas.