Question

$MgC{l}_2\cdot 6H_{2}O$ is obtained from carnalite. Which of the following is true?

• A. $MgC{l}_2\cdot 6H_{2}O$ is left behind in the fused mass
• B. $MgC{l}_2\cdot 6H_{2}O$ solidifies when fused mass is cooled to 176 deg C
• C. $KCl$ remains in the fused state
• D. Solvent extraction is used to extract $KCl$

Answer 1

The correct option is A $MgC{l}_2\cdot 6H_{2}O$ is left behind in the fused mass

Carnalite ($KCl\cdot MgC{l}_2\cdot 6H_{2}O$) is fused and cooled to 176 deg C. Potassium content solidifies and $MgC{l}_2\cdot 6H_{2}O$ remains infused state. Fused mass is separated from deposited $KCl$ and is allowed to cool. The remaining $KCl$ is separated by deposition of carnalite crystals, which crystallizes out first.
$MgC{l}_2\cdot 6H_{2}O$ is left behind in the fused mass.