$M g O$ crystallizes in a cubic type crystal system. The ionic radii for ${M g}^{2 +}$ and $O^{2 -}$ are $0.066$ & $0.140 n m$ respectively. One can conclude that ${M g}^{2 +}$ ions occupy :-
a) a cubic hole in a simple cubic structure.
b) every tetrahedral hole in a close packed structure.
c) an octahedral hole in a cubic close packed structure.
d) every other tetrahedral hole in a close packed structure.

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Solution

The Cation/Anion radius ratio is equal to $(0.066 / 0.140) = 0.4714$ . The given chart suggests that the coordination number is 6. So, the cation would occupy the octahedral hole.
Hence. option (C) is correct.

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The Cation/Anion radius ratio is equal to (0.066/0.140)=0.4714. The given chart suggests that the coordination number is 6. So, the cation would occupy the octahedral hole. Hence. option (C) is correct.

The Cation/Anion radius ratio is equal to $(0.066 / 0.140) = 0.4714$ . The given chart suggests that the coordination number is 6. So, the cation would occupy the octahedral hole.
Hence. option (C) is correct.