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Question
Michael addition is conjugate addition i.e., 1−4 addition. The substrates of the reaction that are involved are the compounds like α,β−unsaturated carbonyl compounds, esters, cyanides, quinones and α,β−unsaturated nitro compounds. The reagent must have at least one acidic hydrogen and must be converted into electrophile in the presence of bases like OH,OR, secondary amine etc.
In the following reaction, the product formed is: CH2=CH−O||C−CH3+CH3−CH2−NO2[(CH3)2CH]2NH−−−−−−−−−−→CHCl3
Michael addition is conjugate addition i.e., 1−4 addition. The substrates of the reaction that are involved are the compounds like α,β−unsaturated carbonyl compounds, esters, cyanides, quinones and α,β−unsaturated nitro compounds. The reagent must have at least one acidic hydrogen and must be converted into electrophile in the presence of bases like OH,OR, secondary amine etc.
In the following reaction, the product formed is: CH2=CH−O||C−CH3+CH3−CH2−NO2[(CH3)2CH]2NH−−−−−−−−−−→CHCl3
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Solution
The correct option is C CH3−C|HNO2−CH2−CH2−C||O−CH3
In Michael addition reaction, the alpha hydrogen of nitro ethane is removed by the base. The alpha carbon acts as a nucleophile and attacks C-4 carbon of but-3-enone.
1,4 addition gives 5-nitro hexan-2-one as the product. The mechanism is as shown below. Here, B is the base.
In Michael addition reaction, the alpha hydrogen of nitro ethane is removed by the base. The alpha carbon acts as a nucleophile and attacks C-4 carbon of but-3-enone.
1,4 addition gives 5-nitro hexan-2-one as the product. The mechanism is as shown below. Here, B is the base.
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