Michael has a box measured $2.1$ meters in length, $1.9$ meters in height and $2.5$ meters in width. What is the surface area of his box can hold?

18.21 m^{2}

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20.21 m^{2}

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27.98 m^{2}

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18.08 m^{2}

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Solution

The correct option is D $27.98 m^{2}$
Surface area $=$ $2 \times$ $($ Length $\times$ width $+$ Length $\times$ height $+$ Width $\times$ height $)$
Length $= 2.1$ m; Height $= 1.9$ m; Width $= 2.5$ m
$= 2 \times (5.25 + 3.99 + 4.75)$
$= 2 \times 13.99$
$= 27.98$ $m^{2}$

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Michael has a box measured 2.1 meters in length, 1.9 meters in height and 2.5 meters in width. What is the surface area of his box can hold?

The correct option is D 27.98m2Surface area = 2× (Length × width + Length × height + Width × height)Length =2.1 m; Height =1.9 m; Width =2.5 m=2×(5.25+3.99+4.75)=2×13.99=27.98 m2

Michael has a box measured $2.1$ meters in length, $1.9$ meters in height and $2.5$ meters in width. What is the surface area of his box can hold?

The correct option is D $27.98 m^{2}$
Surface area $=$ $2 \times$ $($ Length $\times$ width $+$ Length $\times$ height $+$ Width $\times$ height $)$
Length $= 2.1$ m; Height $= 1.9$ m; Width $= 2.5$ m
$= 2 \times (5.25 + 3.99 + 4.75)$
$= 2 \times 13.99$
$= 27.98$ $m^{2}$