Question

# Milk turns sour at 40∘C three times as faster as 0∘C. Hence, Ea in the process of turning of milk sour is 2.303×2×313×27340log(1/3) cal 2.303×2×40273×313log3 cal None of  these 2.303×2×313×27340log3

Solution

## The correct option is D 2.303×2×313×27340log3 K40∘C=Ae−Ea/R×313K0∘C=Ae−Ea/R×2733=e−Ea/R×(1/313−1/273) On taking logs on both sides, you get the required answer

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