milli moles of the solute are present in $350 m L$ solution which is $0.75 M$ .

26.25

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2.625

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.2625

No worries! We‘ve got your back. Try BYJU‘S free classes today!

262.5

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D 262.5
We know that,
Molarity = $\frac{M o l e s o f s o l u t e}{V o l u m e i n l i t r e s o f s o l u t i o n}$
Number of milli-moles $= M o l a r i t y \times [v o l u m e o f s o l u t i o n i n m l]$
$= 0.75 \times 350$
$= 262.5$

Suggest Corrections

Similar questions

Calculate milli-moles of solute in 350 ml solution which is 0.75 M.

350 m L

0.75 M

Calculate milli-moles of solute in 350 ml solution which is 0.75 M.

2000 m L

1 M

Join BYJU'S Learning Program