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Question

Milliequivalents of SeO23 is :

A
5572
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B
5536
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C
1136
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D
116
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Solution

The correct option is B 5536
Millimoles of BrO3 that reacted with SeO23 in equation (i)
=1136 mmol of BrO3
=1136×5 ( n-factor BrO3 in equation (i))

=5536 mEq. of BrO3 mEq. of SeO23 reacted

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