Millikan's oil drop experiment could not find:

\frac{e}{m}

ratio of electron

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charge of electron

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mass of the electron

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velocity of an electron

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Solution

The correct options are
A $\frac{e}{m}$ ratio of electron
B velocity of an electron
D mass of the electron
Millikan's drop experiment could not find:
(i) $\frac{e}{m}$ ratio of electron (it was found by J.J. Thomson)
(ii) Mass of the electron
(iii) Velocity of an electron
It could find the charge of an electron.

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In Millikan’s oil drop experiment the charge of three oil drops X Y Z have been found to be , 0.04 and 0.8 respectively . What could probable charge of electron and the number of electrons attached to this oil drops?

Q. In Millikan's oil drop experiment, the charge of three oil drops

X, Y

and

Z

have been found to be 2, 0.04 and 0.8 respectively. What could be the number of electrons attached to oil drop

X

Q. An oil drop of

10

excess electrons is held stationary under a constant electric field of

3.65 {\times 10}^{4} N C^{- 1}

in Millikan's oil drop experiment. The density of oil is

1.26 g {c m}^{- 3}

. Radius of the oil drop is
(Take

g = 9.8 m s^{- 2}, e = 1.6 \times 10^{- 19} C

)

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Millikan's oil drop experiment could not find:

The correct options are A em ratio of electron B velocity of an electron D mass of the electronMillikan's drop experiment could not find:(i) em ratio of electron (it was found by J.J. Thomson)(ii) Mass of the electron(iii) Velocity of an electronIt could find the charge of an electron.