wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Mini is standing in front of three lights which are turning on and off. She observes the lights lit up after every 10, 12 and 15 minutes respectively. If all the lights lit up together for the last time at 1 P. M. At what time will they lit up together again?

A
1:45 PM
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2 PM
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
3 PM
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
5 PM
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 2 PM
The lights are changing after 10, 12 and 15 minutes respectively.
They have to lit up together.
So, in this case, we have to find out a number which is divisible by 10, 12 and 15 respectively. That is, we have to find L.C.M here.
So,
Prime factors of 10=1×2×5.
Prime factors of 12=1×2×2×3.
Prime factors of 15=1×3×5.
So, the L.C.M of 10, 12 and 15 will be = 2 x 2 x 3 x 5 = 60 minutes = 1 hour.
The lights lit up last at 1 P.M. So, next they will lit up at
= 1 P. M.+ 1 hour
= 2 P. M.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
How Many We Make?
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon