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Question

Minimize and maximize Z=600x+400y
Subject to the constraints
x+2y12
2x+y12
4x+5y20
x0;y0 by graphical method

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Solution

Draw the graph of 2x+y=12 ..... (i)
We get intersection of (i) with the coordinate axes at points (0,12) and (6,0)
Draw the graph of x+2y=12 ..... (ii)
We get the intersection of (ii) with the coordinate axes at points (06) and (120)
Draw the graph of 4x+5y=20..... (iii)
We get the intersection of (iii) with the coordinate axes at points (0,4) and (5,0)
Common shaded region is the feasible region with corner points (5,0),(6,0),(4,4),(0,6),(0,4)
Corner points Z=600x+400y
(0,4)1600 minimum
(0.6)2400
(4,4)4000 maximum
(6,0)3600
(5,0)3000
Minimum value of z=1600 at (0,4)
Maximum value of z=4000 at (4,4)

873967_948581_ans_8e20b8a4ed9440549be9692c7246e520.png

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