wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Minimize Z=7x+y subject to
5x+y5,x+y3,x0,y0.

Open in App
Solution

The intersection point of 5x+y=5 and x+y=3 is (0.5,2.5)
The shaded region shows feasible area according to given constraints.
Value of Z at A=7×0+5=5
Value of Z at B=7×3+0=21
Value of Z at E=7×0.5+2.5=6
Hence, minimum value of Z subject to given constraints is 5.

796154_810904_ans_0fadf8d35cad4263b31165f98bff5f7f.png

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Types of Linear Programming Problem
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon