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Question

Minimized expression for the Boolean function

f(A,B,C,D)=m(0,2,3,4,6,8,9,10,12,14)+d(5,7,13,15)

A

¯¯¯¯¯D+B+¯¯¯¯AC+A¯¯¯¯C

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B

¯¯¯¯¯D+¯¯¯¯AC+A¯¯¯¯C

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C

¯¯¯¯¯D+AC+¯¯¯¯A¯¯¯¯C

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D

¯¯¯¯¯D+B+AC+¯¯¯¯A¯¯¯¯C

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Solution

The correct option is B

¯¯¯¯¯D+¯¯¯¯AC+A¯¯¯¯C


The following K-map has one octet ¯¯¯¯¯D and two quads ¯¯¯¯AC,A¯¯¯¯C



Minimized expression is ¯¯¯¯¯D+¯¯¯¯AC+A¯¯¯¯C

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