Minimum amount of Ag2CO3 (s) required to produce sufficient oxygen for the compelete combusion of C2H2 which produces 11.2ltr of CO2 at S.T.P after combusion is : [Ag =108] Ag2CO3(s)→2Ag(s)+CO2(g)+1/2o2(g) C2H2+5/2O2→2CO2+H2O
A
276g
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B
345g
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C
690g
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D
1380g
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Solution
The correct option is B345g Ag2CO3(s)⟶2Ag(s)+CO2(g)+12O2(g)⟶(1)
C2H2+52O2⟶2CO2+H2O⟶(2)
11.2 litre of CO2 at STP= 11.222.4=0.5 mole of CO2
From equation (2), 2 moles of CO2 is produced from 2.5 mole of O2.
∴0.5 mole of CO2 will be formed from= 2.52×0.5=0.625 mole of O2
Now, 1 mole of Ag2CO3 (equation 1) produces 0.5 mole of O2
0.625 mole of O2 is formed from= 0.625×2=1.25 mole of Ag2CO3 .