1
Question
Minimum number of carbon atoms required in a ketone to show positional isomerism is:
Minimum number of carbon atoms required in a ketone to show positional isomerism is:
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Solution
The correct option is C 5
CH3−CH2CH2−O||C−CH3and CH3−CH2−O||C−CH2CH3⎫⎪
⎪
⎪
⎪⎬⎪
⎪
⎪
⎪⎭ are positional isomers.
Any fewer number of carbons and the result is an aldehyde instead of a ketone.
CH3−CH2CH2−O||C−CH3and CH3−CH2−O||C−CH2CH3⎫⎪ ⎪ ⎪ ⎪⎬⎪ ⎪ ⎪ ⎪⎭ are positional isomers.
Any fewer number of carbons and the result is an aldehyde instead of a ketone.
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