Minimum value of $27^{c o s x} 81^{s i n x}$

- 5

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1 / 5

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1 / 243

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1 / 27

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Solution

The correct option is C $1 / 243$
Since the minimum of 3 cosx+4 sinx is -5.

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Similar questions

x = 243

x^{\frac{1}{5}} \times x^{- \frac{1}{5}}

The value of 4 × (256)^–1/4 ÷ (243)^1/5 is ________.

The value of $(243)^{\frac{1}{5}}$ is

(a) 3 (b)-3 (c) 5 (d) $\frac{1}{3}$

(243)^{- \frac{3}{5}}

\frac{1}{27}

\frac{4}{{(216)}^{\frac{- 2}{3}}} + \frac{1}{{(256)}^{\frac{- 3}{4}}} + \frac{2}{{(243)}^{\frac{- 1}{5}}}

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