Minimum value of 5sin2θ+4cos2θ is
1
2
3
4
Let f(θ) = 5sin2θ+4cos2θ = 4+sin2θ
∴ f(θ) ≥ 4 + 0 (∵sin2θ≥0)
∴ The minimum value of f(θ) is 4.