wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Minimum value of 5sin2θ+4cos2θ is


A

1

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

2

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

3

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

4

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D

4


Let f(θ) = 5sin2θ+4cos2θ = 4+sin2θ

f(θ) 4 + 0 (sin2θ0)

∴ The minimum value of f(θ) is 4.


flag
Suggest Corrections
thumbs-up
37
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Range of Trigonometric Expressions
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon