Minister of Railways, ShriDineshTrivedi travels from Bangalore to Delhi at 50 km/hr and returns at 100 km/hr. What was his average speed?

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66.67

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Solution

The correct option is C 66.67
Average Speed $= \frac{2 \times 50 \times 100}{50 + 100} = \frac{10, 000}{150} = 66.67$ . Distance is kept constant, hence Speed and Time are inversely proportional, hence, we can use Harmonic Mean. $H . M = (\frac{2 a b}{a + b})$ Option(c).

Alternative, Average speed= total distance / total time= 66.67. Option (c).

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Minister of Railways, ShriDineshTrivedi travels from Bangalore to Delhi at 50 km/hr and returns at 100 km/hr. What was his average speed?

The correct option is C 66.67Average Speed =2×50×10050+100=10,000150=66.67 . Distance is kept constant, hence Speed and Time are inversely proportional, hence, we can use Harmonic Mean. H.M=(2aba+b) Option(c). Alternative, Average speed= total distance / total time= 66.67. Option (c).