Minor $M_{33}$ $($ Minor of the element of $i^{th}$ row and $j^{th}$ column $)$ of the determinant $∣ ∣ ∣ ∣ \begin{matrix} 2 & 3 & 5 2 & - 1 & 8 1 & 2 & 4 \end{matrix} ∣ ∣ ∣ ∣$ is

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- 8

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Solution

The correct option is B $- 8$
Given $∣ ∣ ∣ ∣ \begin{matrix} 2 & 3 & 5 2 & - 1 & 8 1 & 2 & 4 \end{matrix} ∣ ∣ ∣ ∣$
$M_{33} =$ minor of $a_{33}$
$= ∣ ∣ ∣ \begin{matrix} 2 & 3 2 & - 1 \end{matrix} ∣ ∣ ∣ = (2 \times - 1) - (3 \times 2)$
$= - 2 - 6 = - 8$

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Minor $M_{33}$ $($ Minor of the element of $i^{th}$ row and $j^{th}$ column $)$ of the determinant $∣ ∣ ∣ ∣ \begin{matrix} 2 & 3 & 5 2 & - 1 & 8 1 & 2 & 4 \end{matrix} ∣ ∣ ∣ ∣$ is

Q. Minor

m_{33}

of the determinant

∣ ∣ ∣ ∣ \begin{matrix} 2 & 3 & 5 2 & - 1 & 8 1 & 2 & 4 \end{matrix} ∣ ∣ ∣ ∣

The minor of the element $3$ in the determinant $∣ ∣ ∣ ∣ \begin{matrix} 1 & 2 & 3 4 & 5 & 6 7 & 8 & 9 \end{matrix} ∣ ∣ ∣ ∣$ is .......

The minor of the element 3 in the determinant $∣ ∣ ∣ ∣ \begin{matrix} 1 & 2 & 3 4 & 5 & 6 7 & 8 & 9 \end{matrix} ∣ ∣ ∣ ∣$ is ___

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Minor M33 (Minor of the element of ith row and jth column) of the determinant ∣∣ ∣∣2352−18124∣∣ ∣∣ is

The correct option is B −8Given ∣∣ ∣∣2352−18124∣∣ ∣∣ M33= minor of a33 =∣∣∣232−1∣∣∣ =(2×−1)−(3×2) =−2−6=−8

Minor $M_{33}$ $($ Minor of the element of $i^{th}$ row and $j^{th}$ column $)$ of the determinant $∣ ∣ ∣ ∣ \begin{matrix} 2 & 3 & 5 2 & - 1 & 8 1 & 2 & 4 \end{matrix} ∣ ∣ ∣ ∣$ is

The correct option is B $- 8$
Given $∣ ∣ ∣ ∣ \begin{matrix} 2 & 3 & 5 2 & - 1 & 8 1 & 2 & 4 \end{matrix} ∣ ∣ ∣ ∣$
$M_{33} =$ minor of $a_{33}$
$= ∣ ∣ ∣ \begin{matrix} 2 & 3 2 & - 1 \end{matrix} ∣ ∣ ∣ = (2 \times - 1) - (3 \times 2)$
$= - 2 - 6 = - 8$